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Prove it.Another case in point of over thinking things. I can prove that in 30 seconds with a dog and 2 doggie treats.
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Prove it.Another case in point of over thinking things. I can prove that in 30 seconds with a dog and 2 doggie treats.
Easy I give the dog one, it knows I have the other and it won't leave me alone till I give it the second treat.Prove it.![]()
No.My calculations are pushing me to strongly considering draining the 4 to 4.5 quarts that is easily removed from the drain plug and replacing the exact amount of fluid when changing the oil every other 5k change instead of 3 to 4 simultaneous flushes at one time at 30k. The same amount of fluid either way.
Legend: Miles on Fluid
Half 1X/10k Method
0k=0k
10k=(50%10k+50%0k)=5k
20k=(50%15k+50%0k)=7.5k
30k=(50%17.5k+50%0k)=8.75k
40k=(50%18.75k+50%0k)=9.325k
50k=(50%19.325k+50%0k)=9.6625k
60k=(50%19.6625k+50%0k)=9.83125k
70k=(50%19.83125k+50%0k)=9.91562k
80k=(50%19.91562k+50%0k)=9.95781k
90k=(50%19.95781k+50%0k)=9.97891k
100k=(50%19.97891+50%0k)=9.98945k
110k=(50%19.98945k+50%0k)=9.99473k
120k=(50%19.99473k+50%0k)=9.99736k
130k=(50%19.99736k+50%0k)=9.99868k
140k=(50%19.99868+50%0k)=9.99934k
150k=(50%19.99934k+50%0k)=9.99967k
160k=(50%19.99967k+50%0k)=9.99984k
170k=(50%19.99984k+50%0k)=9.99992k
180k=(50%19.99992k+50%0k)=9.99996k
190k=(50%19.99996k+50%0k)=9.99998k
200k=(50%19.99998k+50%0k)=9.99999k
Legend: Miles on Fluid
Half 3X/30k Method
0k=0k
10k=10k
20k=20k
30k=(50%30k+50%0k=15k; 50%15k+50%0k=7.5k; 50%7.5k+50%0k)=3.75k
40k=13.75k
50k=23.75k
60k=(50%33.75k+50%0k=16.875k; 16.875k+50%0k=8.4375k; 50%8.4375k+50%0k)=4.21875k
70k=14.21875k
80k=24.21875k
90k=(50%34.21875k+50%0k=17.1094k; 17.1094k+50%0k=8.55469k; 50%8.55469k+50%0k)=4.27734k
100k=14.27734k
110k=24.27734k
120k=(50%34.27734k+50%0k=17.1387k; 17.1387k+50%0k=8.56934k; 50%8.56934k+50%0k)=4.28467k
130k=14.28467k
140k=24.28467k
150k=(50%34.28467k+50%0k=17.1423k; 17.1423k+50%0k=8.57117k; 50%8.57117k+50%0k)=4.28558k
160k=14.28558k
170k=24.28558k
180k=(50%34.28558k+50%0k=17.1428k; 17.1428k+50%0k=8.5714k; 50%8.5714k+50%0k)=4.2857k
190k=14.2857k
200k=24.2857k
I am thinking that a consistent 10k old fluid is better than 4k to 14k to 24k old fluid.
Great post! I appreciate you taking the time to do the calculations. Even though we drive our Badlands very little -- it'll be 4 years old in March and has ~8,000 miles on it -- we'll be at 10K miles next year.My calculations are pushing me to strongly considering draining the 4 to 4.5 quarts that is easily removed from the drain plug and replacing the exact amount of fluid when changing the oil every other 5k change instead of 3 to 4 simultaneous flushes at one time at 30k. The same amount of fluid either way.
Legend: Miles on Fluid
Half 1X/10k Method
0k=0k
10k=(50%10k+50%0k)=5k
20k=(50%15k+50%0k)=7.5k
30k=(50%17.5k+50%0k)=8.75k
40k=(50%18.75k+50%0k)=9.325k
50k=(50%19.325k+50%0k)=9.6625k
60k=(50%19.6625k+50%0k)=9.83125k
70k=(50%19.83125k+50%0k)=9.91562k
80k=(50%19.91562k+50%0k)=9.95781k
90k=(50%19.95781k+50%0k)=9.97891k
100k=(50%19.97891+50%0k)=9.98945k
110k=(50%19.98945k+50%0k)=9.99473k
120k=(50%19.99473k+50%0k)=9.99736k
130k=(50%19.99736k+50%0k)=9.99868k
140k=(50%19.99868+50%0k)=9.99934k
150k=(50%19.99934k+50%0k)=9.99967k
160k=(50%19.99967k+50%0k)=9.99984k
170k=(50%19.99984k+50%0k)=9.99992k
180k=(50%19.99992k+50%0k)=9.99996k
190k=(50%19.99996k+50%0k)=9.99998k
200k=(50%19.99998k+50%0k)=9.99999k
Legend: Miles on Fluid
Half 3X/30k Method
0k=0k
10k=10k
20k=20k
30k=(50%30k+50%0k=15k; 50%15k+50%0k=7.5k; 50%7.5k+50%0k)=3.75k
40k=13.75k
50k=23.75k
60k=(50%33.75k+50%0k=16.875k; 16.875k+50%0k=8.4375k; 50%8.4375k+50%0k)=4.21875k
70k=14.21875k
80k=24.21875k
90k=(50%34.21875k+50%0k=17.1094k; 17.1094k+50%0k=8.55469k; 50%8.55469k+50%0k)=4.27734k
100k=14.27734k
110k=24.27734k
120k=(50%34.27734k+50%0k=17.1387k; 17.1387k+50%0k=8.56934k; 50%8.56934k+50%0k)=4.28467k
130k=14.28467k
140k=24.28467k
150k=(50%34.28467k+50%0k=17.1423k; 17.1423k+50%0k=8.57117k; 50%8.57117k+50%0k)=4.28558k
160k=14.28558k
170k=24.28558k
180k=(50%34.28558k+50%0k=17.1428k; 17.1428k+50%0k=8.5714k; 50%8.5714k+50%0k)=4.2857k
190k=14.2857k
200k=24.2857k
I am thinking that a consistent 10k old fluid is better than 4k to 14k to 24k old fluid.
Hi David,No.
You can't average age of oil.
Adding some new oil does not make the old oil younger.
At 50k 6% of your oil will have 50,000 miles on it.
At 50k 12% of your oil will have 40,000 miles on it.
At 50k 25% of your oil will have 30,000 miles on it.
See where I'm going with this?
To expand this is just a different way to state Peano's axioms. The doggie treat is the natural number, I am the successor function and the dog is treat counter. The fundamental rule of addition. Give me a treat feed the dog, the addition is how many treats did I feed the dog not how I feed the dog. All your grade school math is based on this and the rules that logically fall out of this.Easy I give the dog one, it knows I have the other and it won't leave me alone till I give it the second treat.
No. I'm not saying that at all. I'm saying that is what will happen if you follow through with your experiment.Hi David,
I’m trying to understand… You’re saying that your car has 50k, and the fluid is a mixture of:
6% of the original fluid, that was fresh at 0mi.
12% of the fluid has 40k on it because at 10k you drained 12% of the fluid and replaced it with fresh 0mi fluid.
25% of the fluid has 30k on it because at 20k you drained 25% of the fluid and replaced it with fresh 0mi fluid.
Is that it?
Kind regards,
Larry
You would use 1/3 of the amount of fluid as the 3x30k or 1x10k methods.Honestly, 30k. Drain and fill. But keep in mind its not going to be bright red like old school mercon v.
Joe Strummer, you’re a rascal and you always will be!Why do you go to only 5 decimal places, which equals 1 cm? I need it to the mm...
David,No. I'm not saying that at all. I'm saying that is what will happen if you follow through with your experiment.
Your theory is flawed.