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My calculations are pushing me to strongly considering draining the 4 to 4.5 quarts that is easily removed from the drain plug and replacing the exact amount of fluid when changing the oil every 10k instead of 3 to 4 simultaneous drain and fills at one time at 30k. The same amount of fluid cost either way.
Legend: Average Miles on Fluid Mixture
Half 1X/10k Method
0k=0k
10k=(50%10k+50%0k)=5k
20k=(50%15k+50%0k)=7.5k
30k=(50%17.5k+50%0k)=8.75k
40k=(50%18.75k+50%0k)=9.325k
50k=(50%19.325k+50%0k)=9.6625k
60k=(50%19.6625k+50%0k)=9.83125k
70k=(50%19.83125k+50%0k)=9.91562k
80k=(50%19.91562k+50%0k)=9.95781k
90k=(50%19.95781k+50%0k)=9.97891k
100k=(50%19.97891+50%0k)=9.98945k
110k=(50%19.98945k+50%0k)=9.99473k
120k=(50%19.99473k+50%0k)=9.99736k
130k=(50%19.99736k+50%0k)=9.99868k
140k=(50%19.99868+50%0k)=9.99934k
150k=(50%19.99934k+50%0k)=9.99967k
160k=(50%19.99967k+50%0k)=9.99984k
170k=(50%19.99984k+50%0k)=9.99992k
180k=(50%19.99992k+50%0k)=9.99996k
190k=(50%19.99996k+50%0k)=9.99998k
200k=(50%19.99998k+50%0k)=9.99999k
Legend: Average Miles on Fluid Mixture
Half 3X/30k Method
0k=0k
10k=10k
20k=20k
30k=(50%30k+50%0k=15k; 50%15k+50%0k=7.5k; 50%7.5k+50%0k)=3.75k
40k=13.75k
50k=23.75k
60k=(50%33.75k+50%0k=16.875k; 16.875k+50%0k=8.4375k; 50%8.4375k+50%0k)=4.21875k
70k=14.21875k
80k=24.21875k
90k=(50%34.21875k+50%0k=17.1094k; 17.1094k+50%0k=8.55469k; 50%8.55469k+50%0k)=4.27734k
100k=14.27734k
110k=24.27734k
120k=(50%34.27734k+50%0k=17.1387k; 17.1387k+50%0k=8.56934k; 50%8.56934k+50%0k)=4.28467k
130k=14.28467k
140k=24.28467k
150k=(50%34.28467k+50%0k=17.1423k; 17.1423k+50%0k=8.57117k; 50%8.57117k+50%0k)=4.28558k
160k=14.28558k
170k=24.28558k
180k=(50%34.28558k+50%0k=17.1428k; 17.1428k+50%0k=8.5714k; 50%8.5714k+50%0k)=4.2857k
190k=14.2857k
200k=24.2857k
I am thinking that a consistent 10k old fluid is better than 4k to 14k to 24k old fluid.
I will clarify what each part of my 50k calculation represents…
50k=(50%19.325k+50%0k)=9.6625k
The odometer reading is 50k when I remove the drain plug and only half of the fluid will drain. The other half will not drain as it is trapped in the torque converter.
(50%19.325k+50%0k)=9.6625k
This 50% represents the amount of used oil remaining in the transmission that will not drain as it is trapped in the torque converter.)
50k=(50%19.325k+50%0k)=9.6625k
The 19.325k represents the average mileage of wear on the fluid that won’t drain, which is a calculation of pervious changes every 10k.
(50%19.325k+50%0k)=9.6625k
This 50% represents the new fluid that I will use to replace what was drained.
(50%19.325k+50%0k)=9.6625k
This 0k indicates the new fluid has 0 miles of use.
(50%19.325k+50%0k)=9.6625k
This 9.6625k represents the average mileage of wear of the fluid mixture of 50% fluid with 19.325k of use and 50% of new fluid with 0 miles use.
I hope this better explains what I am thinking, so it is easier to interpret the equation. Thank you for your interest, and if I can explain this better, the findings when understood are interesting to me and possibly reveal this method to be a better choice than the videos that tell us to drain, fill then drain again then fill, then drain again and fill at 30k.
Also, this theory is irrelevant if you flush the transmission, but I am not comfortable with that as I had to rebuild a transmission after getting a scheduled 50k flush years ago. I don’t trust the flush process or the people doing it.
Legend: Average Miles on Fluid Mixture
Half 1X/10k Method
0k=0k
10k=(50%10k+50%0k)=5k
20k=(50%15k+50%0k)=7.5k
30k=(50%17.5k+50%0k)=8.75k
40k=(50%18.75k+50%0k)=9.325k
50k=(50%19.325k+50%0k)=9.6625k
60k=(50%19.6625k+50%0k)=9.83125k
70k=(50%19.83125k+50%0k)=9.91562k
80k=(50%19.91562k+50%0k)=9.95781k
90k=(50%19.95781k+50%0k)=9.97891k
100k=(50%19.97891+50%0k)=9.98945k
110k=(50%19.98945k+50%0k)=9.99473k
120k=(50%19.99473k+50%0k)=9.99736k
130k=(50%19.99736k+50%0k)=9.99868k
140k=(50%19.99868+50%0k)=9.99934k
150k=(50%19.99934k+50%0k)=9.99967k
160k=(50%19.99967k+50%0k)=9.99984k
170k=(50%19.99984k+50%0k)=9.99992k
180k=(50%19.99992k+50%0k)=9.99996k
190k=(50%19.99996k+50%0k)=9.99998k
200k=(50%19.99998k+50%0k)=9.99999k
Legend: Average Miles on Fluid Mixture
Half 3X/30k Method
0k=0k
10k=10k
20k=20k
30k=(50%30k+50%0k=15k; 50%15k+50%0k=7.5k; 50%7.5k+50%0k)=3.75k
40k=13.75k
50k=23.75k
60k=(50%33.75k+50%0k=16.875k; 16.875k+50%0k=8.4375k; 50%8.4375k+50%0k)=4.21875k
70k=14.21875k
80k=24.21875k
90k=(50%34.21875k+50%0k=17.1094k; 17.1094k+50%0k=8.55469k; 50%8.55469k+50%0k)=4.27734k
100k=14.27734k
110k=24.27734k
120k=(50%34.27734k+50%0k=17.1387k; 17.1387k+50%0k=8.56934k; 50%8.56934k+50%0k)=4.28467k
130k=14.28467k
140k=24.28467k
150k=(50%34.28467k+50%0k=17.1423k; 17.1423k+50%0k=8.57117k; 50%8.57117k+50%0k)=4.28558k
160k=14.28558k
170k=24.28558k
180k=(50%34.28558k+50%0k=17.1428k; 17.1428k+50%0k=8.5714k; 50%8.5714k+50%0k)=4.2857k
190k=14.2857k
200k=24.2857k
I am thinking that a consistent 10k old fluid is better than 4k to 14k to 24k old fluid.
I will clarify what each part of my 50k calculation represents…
50k=(50%19.325k+50%0k)=9.6625k
The odometer reading is 50k when I remove the drain plug and only half of the fluid will drain. The other half will not drain as it is trapped in the torque converter.
(50%19.325k+50%0k)=9.6625k
This 50% represents the amount of used oil remaining in the transmission that will not drain as it is trapped in the torque converter.)
50k=(50%19.325k+50%0k)=9.6625k
The 19.325k represents the average mileage of wear on the fluid that won’t drain, which is a calculation of pervious changes every 10k.
(50%19.325k+50%0k)=9.6625k
This 50% represents the new fluid that I will use to replace what was drained.
(50%19.325k+50%0k)=9.6625k
This 0k indicates the new fluid has 0 miles of use.
(50%19.325k+50%0k)=9.6625k
This 9.6625k represents the average mileage of wear of the fluid mixture of 50% fluid with 19.325k of use and 50% of new fluid with 0 miles use.
I hope this better explains what I am thinking, so it is easier to interpret the equation. Thank you for your interest, and if I can explain this better, the findings when understood are interesting to me and possibly reveal this method to be a better choice than the videos that tell us to drain, fill then drain again then fill, then drain again and fill at 30k.
Also, this theory is irrelevant if you flush the transmission, but I am not comfortable with that as I had to rebuild a transmission after getting a scheduled 50k flush years ago. I don’t trust the flush process or the people doing it.
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